{"id":839,"date":"2023-02-02T08:07:51","date_gmt":"2023-02-02T08:07:51","guid":{"rendered":"https:\/\/qpr.ca\/blogs\/physics\/?p=839"},"modified":"2023-02-02T08:10:21","modified_gmt":"2023-02-02T08:10:21","slug":"definition-of-eigenstate","status":"publish","type":"post","link":"https:\/\/qpr.ca\/blogs\/physics\/2023\/02\/02\/definition-of-eigenstate\/","title":{"rendered":"What is the definition of an eigenstate of a hermitian operator?"},"content":{"rendered":"<p>An eigenstate of a quantum observable is a state which results from a measurement of that observable which has produced a precise value; and according to quantum theory this means that it is represented by a normalized eigenvector for the corresponding self-adjoint operator (whose eigenvalue is equal to the observed measurement value).<\/p>\n<p>An eigenvector of an operator [math]A[\/math] is a vector [math]\\Psi[\/math] for which [math]A\\Psi=\\lambda\\Psi[\/math] for some number [math]\\lambda[\/math] (which is called the corresponding eigenvalue).<\/p>\n<p>Source: <em><a href=\"https:\/\/www.quora.com\/What-is-the-definition-of-an-eigenstate-of-a-hermitian-operator\/answer\/Alan-Cooper-5\">(1000) Alan Cooper&#8217;s answer to What is the definition of an eigenstate of a hermitian operator? &#8211; Quora<\/a><\/em><\/p>\n","protected":false},"excerpt":{"rendered":"<p>An eigenstate of a quantum observable is a state which results from a measurement of that observable which has produced a precise value; and according to quantum theory this means that it is represented by a normalized eigenvector for the corresponding self-adjoint operator (whose eigenvalue is equal to the observed measurement value). An eigenvector of &hellip; <a href=\"https:\/\/qpr.ca\/blogs\/physics\/2023\/02\/02\/definition-of-eigenstate\/\" class=\"more-link\">Continue reading <span class=\"screen-reader-text\">What is the definition of an eigenstate of a hermitian operator?<\/span><\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1,4],"tags":[],"topics":[],"class_list":["post-839","post","type-post","status-publish","format-standard","hentry","category-all","category-quora-answers"],"_links":{"self":[{"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/posts\/839","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/comments?post=839"}],"version-history":[{"count":2,"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/posts\/839\/revisions"}],"predecessor-version":[{"id":843,"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/posts\/839\/revisions\/843"}],"wp:attachment":[{"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/media?parent=839"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/categories?post=839"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/tags?post=839"},{"taxonomy":"topics","embeddable":true,"href":"https:\/\/qpr.ca\/blogs\/physics\/wp-json\/wp\/v2\/topics?post=839"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}