A common way to start talking about the EPR “paradox” is with the parable of Bertelman’s socks.
One is green and the other red, and sadly for poor Bertelman, they have been separated and shipped to opposite ends of the universe in boxes to be opened by Alice and Bob.
No-one is surprised to hear that when Alice opens her box and sees a green sock then she knows immediately that Bob’s box contains a red sock. We all know that she could have been informed ahead of time about Bertelman’s sartorial oddity, and of course the socks both started out together. So no-one thinks that Alice’s ability to predict what Bob will see indicates some mysterious ability to instantaneously “turn his sock red”.
So there must be something more to the EPR issue than just knowing that if a pair is split into two boxes and if we find one in one box, then the other must be in the other box.
And indeed there is. The quantum problem is not with the values of one property but how those of different properties can be related. Bertelman’s boring socks were just too simple.
But Dr. Fahni’s funny socks socks are another matter. They are actually iridescent!
Depending on how they are illuminated, one is red and one green or one yellow and one blue.
When either Alice or Bob sees one as red then with the same lighting arrangement the other sees a green one and vice versa. And the same goes for yellow and Blue. And also for Orange and Turquoise. (Oh! I forgot to mention that. There is an intermediate lighting setting under which we see orange and turquoise. And there, as we shall see later, is the rub!)
If Alice sees red, then in the same light Bob sees green (and vice versa), but if he looks in the Yellow-Blue light he sees either with equal probability.
And if Alice sees yellow then in the same light Bob sees blue (and vice versa), but if he looks in the Red-Green light he sees either with equal probability.
In fact we can get this randomness just by starting with a drawer full of pairs of socks in which each left sock is any one of RY,GY,RB,GB (with RY meaning that in Red-Green lighting it shows Red and in Yellow-Blue it shows Yellow) and the corresponding right sock is its opposite (ie GB,RB,GY,RY respectively). Now if a pair is drawn at random and sent to Alice and Bob, then if Alice sees Green she knows that in the Red-Green light Bob will see Red but she has no idea what he will see in the Yellow-Blue light. So it may be getting a little bit complicated to arrange, but there’s still no great mystery in either the randomness or the correlation.
But now let’s look at what happens when the Orange-Turquoise measurement is compared to the other two.
One possible set-up is to build a bigger sock drawer with pairs in which the left sock is of type RYT,GYT,RBT,GBT,RYO,GYO,RBO,GBO and the right always opposite (ie respectively GBO,RBO,GYO,RYO,GBT,RBT,GYT,RYT). If there are equal numbers of each type of pair then when Alice sees Red she still knows that if he looks in RGlight Bob will see Green but if he looks in YBlight he will see either Yellow or Blue with equal probability and if he looks in OTlight he will see Orange or Turquoise with equal probability (and similarly for all the other combinations).
BUT, since Orange is “closer” to Red and Yellow than to Green and Blue, and Turquoise is closer to Green and Blue than to Red and Yellow, Dr. Fahni wants to maintain the opposition by ensuring that whenever Alice sees Red, Bob is actually less likely to see Orange than Turquoise.
In fact when Alice sees Red, if Bob uses OTlight he sees Turquoise just 15% of the time and Orange 85%, and when she sees Green those figures are reversed. Also, if Alice looks in OTlight and sees Orange, then if Bob uses RGlight he will see Red 85% of the time and Green just 15%, and if he uses YBlight he will see Yellow 85% and Blue 15%.
So let’s see how Dr Fahni might have filled up his sock drawer to make this happen. The obvious strategy would be to have unequal numbers of the different pair types with RYT and GBO being least likely, RYO and GBT most likely, and the others somewhere in between.
A first try might be to have just GBT or RYO on the left sock (each matched with the other on the right sock) but this won’t work because we still want GY and GB to be equally likely (and add up to the total proportion green results in RGlight). And similarly for RY and RB.
So in fact we need GY=GB=RY=RB=25%.
But Bell noted that RB=RBT+RBO<=RBT+RBO+RYT+GBO=RBT+RYT+RBO+GBO=RT+BO
So if the situation is symmetric with RT and BO equal, they cannot be less than 12.5%
But with GYT+GBT=85%of50%=RYO+RBO and RYT+RBT=15%of50%=GYO+GBO, we get RT=BO=7.5%.
So the observed correlations cannot be achieved by just selecting at random from a set of pre-prepared pairs of socks.