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Inline formulas:
$\mathbf{\text{Example 2.}}$Let $m$, $n\ne 0$, $k$, and $r\ne 0$ be whole numbers. Explain why $\frac{m(\frac{k}{r})}{n}=\frac{mk}{nr}$.

DisplayMath with inserted text:
$$\mathbf{\text{Step 1:}}\text{By Definition 1, in Module 1, }(nr)(\frac{m(\frac{k}{r})}{n})=r(n(\frac{m(\frac{k}{r})}{n}))=r(m(\frac{k}{r}))=m(r(\frac{k}{r}))=mk$$
DisplayMath with inserted text:
$$\mathbf{\text{Step 2:}}\text{ By Definition 1, in Module 1, }(nr)(\frac{mk}{nr})=mk$$ Inline Formulas w/o textbf:
Step 3: From steps 1 and 2 we have, $(nr)(\frac{m(\frac{k}{r})}{n})=(nr)(\frac{mk}{nr})$ which can only happen if $\frac{m(\frac{k}{r})}{n}=\frac{mk}{nr}$.

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\textbf{Exercise 1.}
Geometrically prove why $A(R(5,b))=A(R(1,5b))$.\
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\textbf{Exercise 2.}
Geometrically prove why $A(R(7,b))=A(R(1,7b))$.\
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\textbf{Exercise 3.}
Let $n$ be any whole number. Explain why $A(R(n,b))=A(R(1,nb))$.\
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\textbf{Example 2.}
Geometrically prove why $A(R(\frac{1}{5},b))=A(R(1,\frac{b}{5}))$.\
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\textbf{Step 1:} The figure below shows that $R(1,b)$ can be divided into five rectangles that are all congruent to $R(\frac{1}{5},b))$. This implies $A(R(1,b))=5A(R(\frac{1}{5},b))$.\

Geometrically prove why $$A(R(\frac{1}{5},b))=A(R(1,\frac{b}{5}))$$

Geometrically prove why $A(R(\frac{1}{5},b))=A(R(1,\frac{b}{5}))$